Actually there is no specific variable existence like string, integer, etc at Perl. All are called Scalar, and it takes all at the same time. The variable type changes from string to integer depending upon the value, or state.
For example depending upon value
For example depending upon state,
But still, you can convert your string into integer easily using int() function.
Or, you can use sprintf() function to do the conversion.
But still, both the conversion are useless. I still suggest you to assign the values directly instead of using the functions.
For example depending upon value
$string = "test"; is a string. But if you set the $string with 10, it will act as integer. $string = 10;For example depending upon state,
$string + 10, here $string will act as integer. And here if($string ge "100") $string will act as string.But still, you can convert your string into integer easily using int() function.
my $string = "10";
$string = int($string); ## convert
print "$string\n";Or, you can use sprintf() function to do the conversion.
my $string = "10";
$string = sprintf("%d", $string); ## convert
print "$string\n";But still, both the conversion are useless. I still suggest you to assign the values directly instead of using the functions.
Comments
while(<>){
chomp;
$x = int($_);
print "SomeSQLCommand($x)";
}
versus leaving out the int
while(<>){
chomp;
$x = $_;
print "SomeSQLCommand($x)";
}
If fed the file
1
2
3
maliciousInput
The first produces
SomeSQLCommand(1)
SomeSQLCommand(2)
SomeSQLCommand(3)
SomeSQLCommand(0)
Whereas the second produces
SomeSQLCommand(1)
SomeSQLCommand(2)
SomeSQLCommand(3)
SomeSQLCommand(maliciousInput)
The int conversion call ensures that the untrustworthy file can only produce integer input.